BTU per pound-°F to Joule per kilogram-Kelvin

1 BTU/(lb·°F) = 4,186.8 J/(kg·K)

Swap: Joule per kilogram-Kelvin to BTU per pound-°F⇄

1 BTU per pound-°F (BTU/(lb·°F)) is equal to 4,186.8 Joule per kilogram-Kelvin (J/(kg·K)).To convert from btu per pound-°f into joule per kilogram-kelvin, calculate using the recognized factor equation: 1 × 4,186.8 = 4,186.8 J/(kg·K). Enter any value into the calculator below for automatic multi-unit calculations across the entire system.

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How to Convert BTU per pound-°F to Joule per kilogram-Kelvin

Exact Formula

To convert from BTU per pound-°F (BTU/(lb·°F)) to Joule per kilogram-Kelvin (J/(kg·K)), apply the standard mathematical equation:

Value in J/(kg·K) = Value in BTU/(lb·°F) × (4,186.8)

Example: 1 × 4,186.8 = 4,186.8 J/(kg·K)

1 BTU per pound-°F (BTU/(lb·°F)) is equal to exactly 4,186.8 Joule per kilogram-Kelvin (J/(kg·K)).

Reverse conversion: 1 J/(kg·K) = 0.000239 BTU/(lb·°F).

BTU per pound-°F to Joule per kilogram-Kelvin Conversion Table

Quick lookup for standard increments from 1 to 100 BTU/(lb·°F)

Reference Table

BTU per pound-°F (BTU/(lb·°F))	Joule per kilogram-Kelvin (J/(kg·K))	Quick Copy
1 BTU/(lb·°F)	4,186.8 J/(kg·K)
2 BTU/(lb·°F)	8,373.6 J/(kg·K)
3 BTU/(lb·°F)	12,560.4 J/(kg·K)
5 BTU/(lb·°F)	20,934 J/(kg·K)
10 BTU/(lb·°F)	41,868 J/(kg·K)
15 BTU/(lb·°F)	62,802 J/(kg·K)
20 BTU/(lb·°F)	83,736 J/(kg·K)
25 BTU/(lb·°F)	104,670 J/(kg·K)
50 BTU/(lb·°F)	209,340 J/(kg·K)
75 BTU/(lb·°F)	314,010 J/(kg·K)
100 BTU/(lb·°F)	418,680 J/(kg·K)

Related Specific Heat Capacity Conversions

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Cluster Links

BTU per pound-°F to Kilojoule per kilogram-Kelvin1 BTU/(lb·°F) = 4.1868 kJ/(kg·K)BTU per pound-°F to Calorie per gram-°C1 BTU/(lb·°F) = 1.0007 cal/(g·°C)

Frequently Asked Questions

Common queries regarding BTU per pound-°F to Joule per kilogram-Kelvin calculation formulas

How many joule per kilogram-kelvin are in 1 btu per pound-°f?

There are exactly 4,186.8 joule per kilogram-kelvin (J/(kg·K)) in 1 btu per pound-°f (BTU/(lb·°F)).

What is the formula to convert from BTU per pound-°F to Joule per kilogram-Kelvin?

To convert BTU per pound-°F to Joule per kilogram-Kelvin: Value in J/(kg·K) = Value in BTU/(lb·°F) × (4,186.8). 1 BTU per pound-°F (BTU/(lb·°F)) is equal to exactly 4,186.8 Joule per kilogram-Kelvin (J/(kg·K)).

How do you convert Joule per kilogram-Kelvin back into BTU per pound-°F?

To convert in reverse from Joule per kilogram-Kelvin to BTU per pound-°F, 1 J/(kg·K) equals approximately 0.000239 BTU/(lb·°F).